期末考

  • 第一題

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    # 第一題
    def Price(ID, p):
        prices = [21000, 20000, 24000, 18000, 35000, 33000, 36500, 38900]
        discount = 1.0
        total_price = 0

        if ID >= 1 and ID <= 8:
            price = prices[ID - 1]
           
            if p == 2:
                discount = 0.96
            elif p >= 3 and p <= 5:
                discount = 0.92
            elif p >= 6 and p <= 10:
                discount = 0.88
            elif p >= 11:
                discount = 0.85
           
            total_price = price * p * discount
           
            if total_price > 200000:
                total_price *= 0.95

        return int(total_price)

    if __name__ == '__main__':
        N = int(input())
        ID = []
        p = []
       
        for i in range(N):
            input_ID = int(input())
            ID.append(input_ID)
            input_p = int(input())
            p.append(input_p)
           
        Sum = 0
        for i in range(N):
            Sum += Price(ID[i], p[i])
           
        print(Sum)

  • 第二題

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    # 第二題
    def TransStr(S):
        ans=0
        for i in range(len(S)):
            if(ord(S[i])-64>26):ans+=ord(s[i])-96
            else:ans+=ord(s[i])-64
        return ans

  • 第三題

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    # 第三題
    def mushroom(plant):
        S=[0,0,0,0,0,0]
        for i in range(len(plant)):
            if(plant[i]==0):S[0]+=1
            if(plant[i]==1):S[1]+=1
            if(plant[i]==10):S[2]+=1
            if(plant[i]==11):S[3]+=1
            if(plant[i]==12):S[4]+=1
            if(plant[i]==13):S[5]+=1
        return S

  • 第四題

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    # 第四題
    def TransYearA(year):
        year=(year-1994)%10
        return year

    def TransYearB(year):
        year=(year-1996)%12
        return year

  • 第五題

    • 第一種方法
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      #第五題
      def NumOfWords(S):
          word_count=0
          for i in range(len(S)-1):
              if(S[i+1]==" " or S[i+1]=="," or S[i+1]=="." or S[i+1]=="-"):
                  if(S[i]!=" " and S[i]!="," and S[i]!="." and S[i]!="-"):word_count+=1
          if(S[-1]!=" " and S[-1]!="," and S[-1]!="." and S[-1]!="-"):
              if(S[-2]!=" " or S[-2]!="," or S[-2]!="." or S[-2]!="-"):word_count+=1
          return word_count
    • 第二種方法
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      #第五題-2
      def NumOfWords(S):
          import re
          words=re.findall(r'\b\w+\b', S)
          return len(words)